Configuration of BGM113 through UART

Squirrel Code
1

Hi,

I’m using BGM113 and I’m trying to understand how to parse the headers for proper processing using the BLE112 as reference (here).

The library class has a function dedicated to parsing the header, but I’m not understanding it completely. This is the section I need to understand from parse_packet(), starting in line 594:

event.msg_type ← (buffer[0] & 0x80);
event.tech_type ← (buffer[0] & 0x78) >> 3;
event.length ← ((buffer[0] & 0x07) << 8) + buffer[1];
event.cid ← buffer[2];
event.cmd ← buffer[3];

I want to choose the 4 bytes a header has, but the code is indexing (?) some other stuff I don’t truly know, because this is what I would’ve done:

event.msg_type ← buffer[0];
event.lenght ← buffer[1];
event.cid ← buffer[2];
event.cmd ← buffer[3];

Why are they doing it differently? This is a screenshot of the reported values in this order (the first one is the result for server.log(buffer)):

  1. event.msg_type ← (buffer[0] & 0x80);
  2. event.tech_type ← (buffer[0] & 0x78) >> 3;
  3. event.length ← ((buffer[0] & 0x07) << 8) + buffer[1];
  4. event.cid ← buffer[2];
  5. event.cmd ← buffer[3];
  6. event.msg_type ← buffer[0];
  7. event.lenght ← buffer[1];
  8. event.cid ← buffer[2];
  9. event.cmd ← buffer[3];

image
image861×151 2.46 KB

Any help would be appreciated!

2

The code in the library is pulling individual bits out.

eg msg_type is just the top bit of the first byte - it’ll be either 0x80 or 0x00. tech_type is the next 4 bits (0x78 is a bitmask of 0b01111000), which is then shifted right 3 places so if - as in this case - bit 5 is set, you’ll see it as 0x04 instead of 0x20 which is what you’d see without the shift).

Length is pulling out the length which has the 3 MSB in the bottom 3 bits of buffer[0], and the 8 LSB in buffer[1].

Your code would only work for packets up to 255 bytes long - a 256 byte packet would have bit 0 of buffer[0] set and zero in buffer[1], for example. You’re ignoring the top 3 MSB.

1 Like
3

Thanks for this useful description Hugo.

Ok, this will help me tons with my adaptation.